7
x - y = 52x + y = 7 (use the substitution method)y = x - 52x + y = 7 (substitute x - 5 for y into the second equation)2x + y = 72x + x - 5 = 73x = 12x = 4Thus x = 4 satisfies both the equations of the system.
Y=52X Your answer is Y. "A number" is X.
x = 0.52 because: 52x + 3 = 30 52x = 30 - 3 52x = 27 x = 27/52 x = 0.52 ( to two decimal places)
-52x + 3 = 7 -52x + 3 = 7 -3 -3 -52x = 4 /52 /52 -x = 1/13 /-1 /-1 x = -1/13
52x - 7 = 33 - 36x + 4 52x + 36x = 33 + 7 + 4 88x = 44 x = 1/2
(2x - 10) + 7 = 52x - 3 = 52x = 8x = 4
"less than AND equals to" is an impossible condition.
It is an equation and the value of x is -3
a = 3 and y = 0
Assuming you meant 52x+3=30 52x=30-3 52x=27 x=27/52 or approximately 0.51923
y=9x=3it equals ......y= 3.334
Several methods exist, for example:Add one equation to the other equation - or add multiples of each equation.Example:x+y = 52x-y = 10Adding the equations results in:3x = 15Now you can solve for x; this is then replaced in one of the original equations.Solve one equation for one variable. Substitute in the other equation. Example:x+y = 52x-y = 10Solve the first equation for x: x = 5 - yReplace in the second equation: 2(5-y) - y = 10Once again, you can solve for one variable, then replace that variable in one of the original equations.Solve both equations for the same variable.Example:x+y = 52x-y = 10Solve each equation for x:Equation 1: x = 5 - yEquation 2: 2x = 10 - y; x = 5 - y/2Equate the right sides of both equations (this is valid, since they are both equal to x):5 - y = 5 - y/2