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y=7x+1 is a linear equation with a slope of 7 and y-intercept at (0,1). It contains two variables, y and x and cannot be solved unless one variable is given. The x-intercept to this equation is (-1/7,0). The first derivative of the equation would be y=7, a horizontal line with y-intercept (0,7). The second derivative and jerk cannot be taken.

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Q: What is y equals 7x plus 1?

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The y-intercept for the equation y=-7x+1 is (0,1). When x=0, y= -7*0+1 = 1

(2, 1)

Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0

4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)

2y + 7x + y-1?

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7x + y + z = 6 7x + y + 4z = 9 y + x = 6 Take the first two statements and subtract them. 7x + y + z = 6 7x + y + 4z = 9 _____________ 0 + 0 - 3z = -3 Therefore: z = 1 Then you are left with: 7x + y + 1 = 6 7x + y + 4 = 9 which is impossible, so this is an impossible equation.

7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8

7x + y = 4y = 4 - 7x

The y-intercept for the equation y=-7x+1 is (0,1). When x=0, y= -7*0+1 = 1

It is: y = -7x+1 in slope intercept form

7x+y=6

(2, 1)

y=-10x-4

The Y intercept of y=7x+10 is 10.

Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0

4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)

y is increased by 7