A polygon with n sides has n*(n-3)/2 diagonals.
So you need to solve n*(n-3)/2 = 54
n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.
Since a polygon cannot have a negative number of sides, the answer is 12.
A polygon with n sides has n*(n-3)/2 diagonals.
So you need to solve n*(n-3)/2 = 54
n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.
Since a polygon cannot have a negative number of sides, the answer is 12.
A polygon with n sides has n*(n-3)/2 diagonals.
So you need to solve n*(n-3)/2 = 54
n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.
Since a polygon cannot have a negative number of sides, the answer is 12.
A polygon with n sides has n*(n-3)/2 diagonals.
So you need to solve n*(n-3)/2 = 54
n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.
Since a polygon cannot have a negative number of sides, the answer is 12.
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A polygon with n sides has n*(n-3)/2 diagonals.
So you need to solve n*(n-3)/2 = 54
n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.
Since a polygon cannot have a negative number of sides, the answer is 12.
A twelve sided polygon.
It is a dodecagon which has 12 sides Check: 0.5*(144-36) = 54 diagonals
It is: 0.5*(144-36) = 54 diagonals
54 Diagonals. * * * * * A polygon with n sides has 1/2*n*(n-3) diagonals. So a decagon would have 1/2*10*7 = 35 diagonals. How the Community answer got 54 is anybody's guess!
There is no such polygon that has 95 diagonals because a 15 sided polygon has 90 diagonals and a 16 sided polygon has 104 diagonals.