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Melyssa Goodwin
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∙ 3y agoThis answer is:
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∙ 12y ago1 and 14.
To solve this algebraically, set up a systems of equations
a + b = 15 which can be rewritten as a = 15 - b
a*b = 14
therefore, substitute this value into the second equation.
(15-b)b = 14
15b - b^2 - 14 = 0
b^2 - 15b + 14 = 0
(b - 1)(b-14) = 0
1 and 14
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