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There are infinitely many possible solutions. Given ANY number to be next in sequence, I can find a polynomial (of order 5) which will do the trick.

The simplest polynomial is

Un =

(5563n4 - 50598n3 + 167717n2 - 229194n + 109080)/24 for n =

1, 2, 3, ...

and according to it, the next number is the sequence would be 43,842.



There are infinitely many possible solutions. Given ANY number to be next in sequence, I can find a polynomial (of order 5) which will do the trick.

The simplest polynomial is

Un =

(5563n4 - 50598n3 + 167717n2 - 229194n + 109080)/24 for n =

1, 2, 3, ...

and according to it, the next number is the sequence would be 43,842.



There are infinitely many possible solutions. Given ANY number to be next in sequence, I can find a polynomial (of order 5) which will do the trick.

The simplest polynomial is

Un =

(5563n4 - 50598n3 + 167717n2 - 229194n + 109080)/24 for n =

1, 2, 3, ...

and according to it, the next number is the sequence would be 43,842.



There are infinitely many possible solutions. Given ANY number to be next in sequence, I can find a polynomial (of order 5) which will do the trick.

The simplest polynomial is

Un =

(5563n4 - 50598n3 + 167717n2 - 229194n + 109080)/24 for n =

1, 2, 3, ...

and according to it, the next number is the sequence would be 43,842.

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12y ago

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There are infinitely many possible solutions. Given ANY number to be next in sequence, I can find a polynomial (of order 5) which will do the trick.

The simplest polynomial is

Un =

(5563n4 - 50598n3 + 167717n2 - 229194n + 109080)/24 for n =

1, 2, 3, ...

and according to it, the next number is the sequence would be 43,842.

User Avatar

Wiki User

12y ago
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Q: What number comes next in sequence 107 241 642 2568 12840?
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