1 and 7.
The highest number that both 63 and 14 go into is infinity. They go into infinity an infinite number of times (as does every other number). I'm not sure if you have asked the right question, but if you have then the answer is infinity. If, however, you meant, "what is the highest common factor of both 63 & 14?", then the answer is 7. 63 = 9 * 7 and 14 = 2 * 7.
No. 63 is not evenly divisible by 14.
The expression for 14 less than the quotient of 63 and a number ( h ) can be written as ( \frac{63}{h} - 14 ). Here, ( \frac{63}{h} ) represents the quotient of 63 and ( h ), and subtracting 14 gives the required expression.
14 can go into 63 four times, with a remainder. When you divide 63 by 14, you get 4, since 14 multiplied by 4 equals 56. This leaves a remainder of 7, as 63 minus 56 equals 7. Therefore, 14 goes into 63 a total of 4 times.
The algebraic expression for 14 less than the quotient of 63 and the number H is ( \frac{63}{H} - 14 ). This expression first calculates the quotient of 63 and H, and then subtracts 14 from that result.
7 7 x 2 = 14 7 x 9 = 63
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
Well, honey, if you want to divide 882 by 14, the answer is 63. So, 14 can go into 882 a total of 63 times. Math doesn't lie, darling.
1 and 7.
Nine will go into 63 seven times.
63 goes into 917 14 times with remainder 35.
Seven goes into both 63 and 77