$no = 23; if($no % 6 == 0) { echo "$no is divisible by 6"; }else{ echo "$no is NOT divisible by 6"; }
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.
23 is not divisible by 7.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
Multiply the last digit by 7. Subtract that number from the remaining digits. If that number is divisible by 23, then the original number is divisible by 23.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
if a number is divisible by 2 and 3 then its divisible by 6
If a number is divisible by 2 and 3, it is divisible by 6.
23 is a prime number so it is not divisible by 3. It is only divisible by 1 and 23. Dividing 23 by three gives the result of 7.6r
The product of any number and 6 would be divisible by 6.
Since 3 is a factor of 6, any number divisible by 6 is also divisible by 3. But since 2 is also a factor of 6, then any number divisible by 6 must also be divisible by 2. This means that any number divisible by 6 is an even number. So if a number is odd and it is divisible by 3, then it is not divisible by 6. For example, 12 is divisible by 3, but since it is even, it is also divisible by 6. But 15 is divisible by 3, and it is odd, so it is not divisible by 6.