no because 31 is not an even number. Therefore an even number can not be a factor of it. 31 is a prime number so the only factors it has are 1 and 31
4 is greater than 3 and is a factor of 20.
If it is even, divide it by two. If your second number is also even, your original number is divisible by four. This is a necessary and sufficient condition; A cannot be divisible by four if either of {A, B} is odd.If either your original number or your second number were odd, then the original number is not divisible by four.Proof of this rule (by cases):Where applicable, A = 2B.A even, B even: B = 2m (m is a whole factor of B) and therefore A = 4m, therefore 4 is a factor of A by definition of a factor.A even, B odd: if B is odd, it does not have 2 as a whole factor. Therefore there exists no whole m such that A = 4m, and therefore 4 is not a factor of A by definition of a factor.A odd: A cannot have any even factors. 4 is even. Therefore 4 is not a factor of A.
60 is an even number and also a factor of itself
Assuming the second even number is equal to 4 or greater, than the highest common factor of the two numbers is equal to an even number 2 or greater. Why can't an odd factor be used? Any odd factor must be multiplied by (at least) 2 to create an even product (ie. the 1st even number). That same odd factor must be multiplied by (at least 2) and any other number to create a 2nd even product, thereby making the Greatest Common Factor (at least) 2 times the odd number....which is an even number.
198 is the greatest three-digit even number that has no factor equal to 4.
4 is an even number.
4 is not a factor of 998
No. All the multiples of 4 are even numbers.
no because 31 is not an even number. Therefore an even number can not be a factor of it. 31 is a prime number so the only factors it has are 1 and 31
Any even number has at least one even factor.
106
998
102
4 is greater than 3 and is a factor of 20.
If it is even, divide it by two. If your second number is also even, your original number is divisible by four. This is a necessary and sufficient condition; A cannot be divisible by four if either of {A, B} is odd.If either your original number or your second number were odd, then the original number is not divisible by four.Proof of this rule (by cases):Where applicable, A = 2B.A even, B even: B = 2m (m is a whole factor of B) and therefore A = 4m, therefore 4 is a factor of A by definition of a factor.A even, B odd: if B is odd, it does not have 2 as a whole factor. Therefore there exists no whole m such that A = 4m, and therefore 4 is not a factor of A by definition of a factor.A odd: A cannot have any even factors. 4 is even. Therefore 4 is not a factor of A.
Yes, all even numbers have a factor of two due the fact that the are of an even sequence and can be divisible by two which is also an even number. Any number that is even is not prime because is can be divided by the factor 2, but two itself is a prime number as its only factors are itself and 1. All even number have to have a factor of two e.g 4 can be divided by two, as well as 6,8,10,12,14,16,18,20 and so on.