A very fast and effective way to do this would be a factor tree. I can't draw it on here, as I have no tools, but here is a crude example:
114=
6 * 19
2 * 3 * 19
Here is an explanation in words:
114/6=19, hence
114=
6 * 19
If you have ever been taught how to prime factorize, you must know to reduce it to prime numbers. 19 is already a Prime number, so you leave it alone. 6 is not, and the primefactorization of 6 is 2*3, hence the prime factorization of 114 is 2*3*19.
It is simple if you know how to prime factorize.
The first 15 multiples of 114 are:
114, 228, 342, 456, 570, 684, 798, 912, 1026, 1140, 1254, 1368, 1482, 1596, 1710 . . . ∞
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 111*k, where k is an integer, is evenly divisible.
2, 3, 6, 19, 38 and 57
456 and its multiples.
1, 2, 3, 6, 19, 38, 57, 114.
Multiples of 111.
1, 2, 3 and 6 are their common factors.
The lists of numbers divisible by and not divisible by 600 are both infinite.
All even numbers are divisible by 2.
Odd numbers
51234 is divisible by itself and any of its multiples
Every number is divisible by any non-zero number. Any element of the set of numbers of the form 4518*k where k is an integer is evenly divisible.
No. 111 is an odd number; only even numbers are divisible by 2.
NO! of course not. numbers divisible by 5 end in 5 or (and) 0!
37, 74, 111 and so on.
How many numbers are divisible by 9 between 5 and 1000²
111 of them.
Perhaps you mean twin primes? In which case the answer is no: 111 is divisible by 3 so is not prime.
111 is divisible by 3 and 37
Trivially not, since both of them are divisible by 3.
1, 3, 9, 37, 111, 333
The first number in this range divisible by 9 is 9 itself...9 = 1 x 9 The last number in the range is 999 = 111 x 9 So there are 111 numbers between 1 and 1000 that are divisible by 9.
22,200 is a number that can be divisible by 111 and 200.
111 is divisible by: 1, 3, 37, 111.