101
1000, 1020, 1040, 1060, 1080, and 1100
1111 is the only one.
If you think about the digits, you can rewrite them as ABBA, with A being one digit and B being another: A can be 1-9 and B can be 0-9. Since A has to be 1, B can be 0-9, leaving 10 palindromic numbers.
1100
One: 1001A palindrome reads the same forwards and backwards. Therefore for a 4 digit number:The first and last digits must be the sameThe middle two digits must be the sameStarting with 1000, the first palindrome will be 1001, then 1111, 1221, 1331, ...As it must be less than 1100, there is only one, 1001.
1100
1000, 1020, 1040, 1060, 1080, and 1100
The number between 1100 and 1200 is 1150. This number falls exactly halfway between 1100 and 1200 on the number line. It can be calculated by finding the average of the two numbers: (1100 + 1200) / 2 = 1150.
26,200 - 1,100 = 25,100
There are uncountably infinitely many real numbers between 1080 and 1100. There are 21 integers between 1080 and 1100, including the "endpoints." They are: 1080, 1081, 1082, 1083, 1084, 1085, 1086, 1087, 1088, 1089, 1090, 1091, 1092, 1093, 1094, 1095, 1096, 1097, 1098, 1099, 1100.
1111 is the only one.
If you think about the digits, you can rewrite them as ABBA, with A being one digit and B being another: A can be 1-9 and B can be 0-9. Since A has to be 1, B can be 0-9, leaving 10 palindromic numbers.
0xc = 1100 Hexadecimal digits use exactly 4 binary digits (bits). The 0x0 to 0xf of hexadecimal map to 0000 to 1111 of binary. Thinking of the hexadecimal digits as decimal numbers, ie 0x0 to 0x9 are 0 to 9 and 0xa to 0xf are 10 to 15, helps with the conversion to binary: 0xc is 12 decimal which is 8 + 4 → 1100 in [4 bit] binary.
1100
Since all the numbers in that range start with "11", there is really only one option!
8924 is the number that comes 1100 numbers after 7824.
1100