Themselves because they are all prime numbers.
The prime factors are: 2 3 5
Yes. The first 5 prime numbers are 2, 3, 5, 7, and 11.
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
Its prime factors are: 3, 5 and 7
The prime numbers (factors) of 75 are: 3 and 5
The prime factors are: 2 3 5
Yes. The first 5 prime numbers are 2, 3, 5, 7, and 11.
The prime numbers from 1 to 7 are 2, 3, 5 and 7.
2, 3, 5 and 7
Its prime factors are: 3, 5 and 7
average of first five prime numbers = 5.6 first five prime numbers = 2, 3, 5, 7, 11average = sum of first prime numbers/5= (2 + 3 + 5 + 7 + 11)/5= 28/5= 5.6
The prime numbers (factors) of 75 are: 3 and 5
The first five prime numbers are 1, 2, 3, 5, and 7.
3, 5, and 7 are three prime numbers whose average is 5.
multiply these prime numbers together to get your answer
The first four prime numbers after 3 are: 5, 7, 11, 13
They are: 2, 3, 5 and 7