As a product of its prime factors: 2*2*2*2*7 = 112
For example how about 2*112 = 224
Let the two numbers be represented by a and b. Then, ab = 112 so b = 112/a. And, a + b = -32......substituting for b this becomes :- a + 112/a = -32........multiplying throughout by a a2 + 112 = -32a.......re-arranging a2 + 32a + 112 = 0 This equation factors (a + 4)(a + 28) = 0 When (a + 4) = 0 then a = -4......and thus b = -28 When (a + 28) = 0 then a = -28....and thus b = -4 The two numbers are -4 and -28.
1 and 112 2 and 56 4 and 28 7 and 16 8 and 14 112 and 1 0.5 and 224 0.25 and 448 0.1 and 1120
-4 - 112 = -4 - 121 = -125 (-4 - 11)2 = -152 = 225
7 x 16 = 112.
112 and 2 are 2 numbers
There are infinitely many possible pairs of numbers. An easy pair to remember is 1 and 112.
As a product of its prime factors: 2*2*2*2*7 = 112
130
For example how about 2*112 = 224
Either (a) multiply 112 by 0, by 1, by 2, etc., or (b) starting with zero, add 112 repeatedly to get the following numbers in the sequence of multiples.
Let the two numbers be represented by a and b. Then, ab = 112 so b = 112/a. And, a + b = -32......substituting for b this becomes :- a + 112/a = -32........multiplying throughout by a a2 + 112 = -32a.......re-arranging a2 + 32a + 112 = 0 This equation factors (a + 4)(a + 28) = 0 When (a + 4) = 0 then a = -4......and thus b = -28 When (a + 28) = 0 then a = -28....and thus b = -4 The two numbers are -4 and -28.
1 and 112 2 and 56 4 and 28 7 and 16 8 and 14 112 and 1 0.5 and 224 0.25 and 448 0.1 and 1120
224
Since the numbers 15 and 112 share no common positive integer factors, the proper fraction 15/112 is already expressed in its simplest form.
(112, -1) (56, -2) (28, -4) (16, -7) (14, -8)(-112, 1) (-56, 2) (-28, 4) (-16, 7) (-14, 8)