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If f(x) = 0 is a quadratic equation in x, then the roots of f(x) are the values of x which make the equation true.
If f(x) = ax^2 + bx + c = 0
then the roots are
[-b - sqrt(b^2 - 4ac)]/(2a)] and [-b + sqrt(b^2 - 4ac)]/(2a)].
Conversely,
given the roots of f(x) = 0 are s and t then
f(x) = x^2 - (s+t)*x + st.
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Formula of quadratic equation if roots are given?
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
What are quadratic equations with real roots?
If the discriminant of the quadratic equation is zero then it will have 2 equal roots. If the discriminant of the quadratic equation is greater than zero then it will have 2 different roots. If the discriminant of the quadratic equation is less than zero then it will have no roots.
What is the sum of the roots of the equation -x squared equal to 3x plus 4?
It has no roots because the discriminant of the given quadratic equation is less than zero.
How do you solve a quadratic equation graphically?
The roots of the quadratic equation are the x-intercepts of the curve.
How do you solve 12x squared plus 9x plus 15 equals 0 with quadratic formula?
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
