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Jordan-4 x 3 = -12, and -4 + 3 = -1.
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X + Y = -1
XY = -12
You want two numbers, X and Y. Multiplied together they will equal 12; if one of them is negative they will equal -12. They are one apart from each other, and if the larger one is negative their sum will be -1.
12 = 2 x 2 x 3, and the factors 4 and 3 are one apart from each other. If you make the larger one negative, it will fit both equations above.
The complexity of this question lies in its having a negative factor; if you ignore that at first, the answer is easy to see.
To solve it algebraically, you end up with: -X2 - X + 12 = 0; then you have to solve the quadratic.
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What times what equals 28 and 12?
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9 divided by 9 plus3 times 12?
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