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[33 + SQRT (1033)]/2 & [33 - SQRT (1033)]/2
You have two equations & two unknowns:
x*y = 14
x + y = 33
Rearrange the first equation for y * substitute into the second. Then solve for x.
y = 14/x
x + (14/x) = 33
x *[x + (14/x) = 33]
x2 + 14 = 33x
x2 - 33x + 14 = 0
Use the quadratic equation to solve for x, where a=1, b=-33, c=14 and you should get the answers listed above. Hope that helps.
14 goes into 33 two times, as 14 multiplied by 2 equals 28, which is less than 33. If you try to multiply 14 by 3, you get 42, which exceeds 33. Therefore, 14 fits into 33 a total of 2 times with a remainder of 5.
-103
33 x 3.14 = 103.62
11 x 3 = 33
It is 33 times 50 = 1650