What times what equals eight but when added it equals negative six?

Answer 1

-2 and -4.

The factor pairs of 8 are: {2, 4}, {1, 8}, {-1, -8}, {-2, -4}

The sum of the pairs are 6, 9, -9, -6;

Thus the required pair is {-2, -4}.

Answer 2

xy = 8 and x + y = -6; y = -6 -x; so xy = x(-6-x) = 8;-6x-x^2 - 8 = 0x^2 +6x+8 = 0(x+4)(x+2) = 0x = -4 and y = -2Thus the numbers are negative 4 and negative 2