Here's how I did it:
I set up my two equations:
xy=540
x+y=12
Then, by subtraction
x=12-y
By substitution:
xy=540
(12-y)y=540
12y-y2=540
-y2+12y-540=0
Through the quadratic formula...
y=6 ± -6i√14
If you use addition for y, then you should subtract for x, so that x + y = 12
16.5
1660
6
28
First, multiply the original number by 10. Then multiply the original number by 2. Add the two answers that you got and you have just multiplied by 12. For Example: 7x12=(7x10)+(7x2) 70+14 84
552
16.5
1660
702
-121
71
1.52
6
Multiply the three-digit number by the one's digit, or last digit, of the two-digit number. That is your first part. Now multiply by the second-to-last digit, or ten's digit, and multiply the result by 10. That is your second part. Add the two parts and that is your answer.
7
28
32