-4
The two numbers that add to give 1 and multiply to give -4 are 4 and -3. When you add them, 4 + (-3) = 1, and when you multiply them, 4 × (-3) = -12. So, the correct answer is 4 and -3.
The two numbers that multiply to -11 and add to -5 are -11 and 1. When you multiply -11 and 1, the result is -11. When you add them together, -11 + 1 equals -10, not -5. Therefore, there are no two real numbers that satisfy both conditions.
The two numbers that add to equal -14 and multiply to equal -15 are -15 and 1. When you add them together, -15 + 1 equals -14. Their product, -15 × 1, equals -15.
How about: 5*5 = 25 or 1*25 = 25
-103
They are -1 and -3
The two numbers that add to give 1 and multiply to give -4 are 4 and -3. When you add them, 4 + (-3) = 1, and when you multiply them, 4 × (-3) = -12. So, the correct answer is 4 and -3.
The two numbers that multiply to -11 and add to -5 are -11 and 1. When you multiply -11 and 1, the result is -11. When you add them together, -11 + 1 equals -10, not -5. Therefore, there are no two real numbers that satisfy both conditions.
6 - (5+1, 4+2, 3+3) 4 - (4x1, 2x2)
The two numbers that add to equal -14 and multiply to equal -15 are -15 and 1. When you add them together, -15 + 1 equals -14. Their product, -15 × 1, equals -15.
How about: 5*5 = 25 or 1*25 = 25
-103
For a pair of numbers, the answer is the complex conjugate pair: 12.5 ± 21.9943 i where i is the imaginary square root of -1.
-25
The two numbers that multiply to 5 and add to -6 are -1 and -5. When multiplied, -1 and -5 equal 5, and when added together, they sum to -6. Thus, the solution to the problem is -1 and -5.
The numbers that multiply to -6 and add to -1 are 2 and -3. When you multiply 2 and -3, you get -6, and when you add them together, you get -1. Thus, the solution is 2 and -3.
The numbers are: 9 + square root of 129 and 9 - square root of 129