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Cletus Quigley
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∙ 3y agoThis answer is:
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∙ 13y agoThis is only true if you use complex numbers.
Given:
a + b = -4
ab = 14
Then:
a(-4 - a) = 14
-a2 - 4a - 14 = 0
a2 + 4a + 14 = 0
a2 + 4a + 4 = -10
(a + 2)2 = -10
a + 2 = ± i(10)1/2
a = -2 ± i(10)1/2
So the two numbers that meet those conditions would be -2 + i√10 and -2 - i√10
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