177
Chat with our AI personalities
Let the numbers be x and y. So we have,
xy = 135
x + y = 42, which yield y = 42 - x (use substitution method to solve the linear system of the equations)
xy = 135 (substitute y by 42 - x)
x(42 - x) = 135
42x - x2 = 135 (subtract 135 to both sides)
42x - x2 - 135 = 0 (multiply by -1 to both sides)
x2 - 42x + 135 = 0 (use the quadratic formula to solve for x)
x = [-(-42) ± √[422 - 4(1)(135)]]/2(1)
x = [42 ± √(1,764 - 540)]/2
x = (42 ± √1,224)/2
x = 42/2 ± (√1,224)/2
x = 21 ± √1,224/4 = 21 ± √306
x ≈ 21 ± 17.5
x ≈ 21 + 17.5 or x ≈ 21 - 17.5
x ≈ 38.5 or x ≈ 3.5
y = 42 - x (replace x with 38.5 or 3.5)
y = 42 - 38.5 = 3.5, so that
y = 3.5 or y = 38.5
Thus, the numbers are approximately to 38.5 and 3.5
To answer this question you first need to break 135 down into its prime factors: 135 = 3x3x3x5 In order to find two numbers that multiply to make 135, one of them must be a product of a certain combination of these numbers (and 1) and the other must have the rest. Therefore the possible pairs are: 1 and 135 3 and 45 5 and 27 9 and 15
The two numbers you are looking for are -15 and 4. When you multiply -15 and 4, you get -60, and when you add them together, you get -13.
Product = multiply.
141
There are no two consecutive numbers that add or multiply to 102.