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There are no two real numbers that solve the problem.

With complex numbers, the solution is:

(-4 + i√82) and (-4 - i√82)

Q: What two numbers multiply to equal 98 and the sum of the two numbers equals -8?

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The numbers are -2 and 28

the two numbers are 14 and - 4.

The sum of the prime numbers 11 and 53 equals 64.

-9

This is the way I would do it: The sum of the 1st & 100th numbers = the sum of the 2nd & 99th numbers = the sum of the 3rd & 98th numbers all the way to the sum of the 50th & 51st numbers; each of the sums equals 200. So I would multiply 200 by 50 (10000).

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The numbers are -2 and 28

the two numbers are 14 and - 4.

-356

The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953

The sum of the prime numbers 11 and 53 equals 64.

It's unclear whether you want two numbers that add to a sum or multiply to a product. 25 x 4 = 100 25 + 75 = 100

-9

3.268 and 6.372 (approx)

This is the way I would do it: The sum of the 1st & 100th numbers = the sum of the 2nd & 99th numbers = the sum of the 3rd & 98th numbers all the way to the sum of the 50th & 51st numbers; each of the sums equals 200. So I would multiply 200 by 50 (10000).

It depends on whether you want multiply or sum!

6 and 9. If you take 6 and multiply it times 3, it is 18. If you take 9 and multiply it times 2, it equals 18.

It is not possible to multiply two prime numbers and get 90. You can add 43 and 47.