What two factors equal 72 with a difference of 14?

Answer 1

110

Answer 2

First you have to transform the problem into equations.
We have two unknow numbers, let's call them a and b

the sum of the two numbers if 72 would be written
a+b = 72

their difference is 48 would be written
a-b=48
(one of the number is greater than the other, we chose to say that a was the greatest)

Now, we use the fact that we can add a same quantity to both part of an equation and keep this equation true. As a-b equals 48, it is the same quantity, and we can add it to both part of the equation a+b = 72. For the left part, with the unknown numbers, we add the part containing also unknow numbers (a-b) and for the right part (a value) we add the part with a value (48)

a+b = 72
<=> a+b+a-b = 72 + 48
<=> a+a = 120
<=> a = 60

Now we have a. So we can substitute its value in any of the equations, for example the first who becomes
60 + b = 72
<=> 60 + b - 60 = 72 - 60 (we add -60, a same quantity, to both side of the equation)
<=> b = 12

(The mathematic reasoning to solve this problem have been shown in bold)

Answer 3

The common factors are 1, 2, 3, 4, 6, 8, 12, 24.

Answer 4

48 = 1 x 48, 2 x 24, 3 x 16, 4 x 12, 6 x 8

Answer 5

36 + 2 = 38

36(2) = 72

Answer 6

1, 2, 3, 4, 6, 8, 12, 24.

Answer 7

144, 288, 432 . . .

Answer 8

1 2 3 4 6 8 12 24

Answer 9

4 and 18

Answer 10

4 & 12.