I set up two equations:
xy=-270
x+y=-49
For the second equation, I subtracted y from both sides, and I was left with x=-49-y
I substituted -49-y into the first equation to get (-49-y)y=-270
I distributed the y, -49y-y2=-270
I divided both sides by -1, 49y+y2=270
I subtracted 270 from both sides (and rearranged it a bit, doesn't change the value of the equation) to get y2+49y-270
Some of you will recognize this as a quadratic, and the best way to solve this is with the quadratic formula!
After plugging in the numbers into the quadratic equation and simplifying, I was left with (-49±59)/2
x = 5 , x = -54
No i need help
-287
66 X 2=132
-291
because the negatives cross out each other and your left with positive numbers to multipy.
No i need help
-287
They are: 7 times 7 = 49
66 X 2=132
-291
4760
because the negatives cross out each other and your left with positive numbers to multipy.
The sum of three odd numbers is odd but 270 is even, therefore there are no three odd numbers that add to 270. Similarly the product of two of more odd numbers is odd but 270 is even, therefore there are no three odd numbers that multiply together to get 270.
5 times 54 equals 270
There are infinitely many possible answers. Some of these are: 1*24, 10*2.4 (-3)*(-8)
14
To find two numbers with a greatest common factor (GCF) of 15 and a least common multiple (LCM) of 270, we can use the relationship between GCF, LCM, and the two numbers. The relationship is LCM(a,b) = (a * b) / GCF(a,b). Given GCF = 15 and LCM = 270, we can substitute these values into the formula to get 270 = (15 * b) / 15. Solving for b gives us b = 270 / 15 = 18. Therefore, the two numbers are 15 and 18.