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There cannot be such shapes.

The Euler characteristic for each shape requires Faces + Vertices = Edges + 2

Therefore, for 2 shapes, F + V = E + 4

The equation fails in this case.

There cannot be such shapes.

The Euler characteristic for each shape requires Faces + Vertices = Edges + 2

Therefore, for 2 shapes, F + V = E + 4

The equation fails in this case.

There cannot be such shapes.

The Euler characteristic for each shape requires Faces + Vertices = Edges + 2

Therefore, for 2 shapes, F + V = E + 4

The equation fails in this case.

There cannot be such shapes.

The Euler characteristic for each shape requires Faces + Vertices = Edges + 2

Therefore, for 2 shapes, F + V = E + 4

The equation fails in this case.

More answers

There cannot be such shapes.

The Euler characteristic for each shape requires Faces + Vertices = Edges + 2

Therefore, for 2 shapes, F + V = E + 4

The equation fails in this case.

Q: What two shapes has 10 faces 16 edges and 16 vertices?

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A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.

Any polyhedron can be deformed (its angles changed) without affecting the number of edges, vertices or faces.

Three faces, two edges and 0 vertices.

Three faces, two edges and 0 vertices.

You cannot have such a shape because either the shapes must meet at an edge or the vertices must be joined by an edge.

Related questions

A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.

cube and cuboid

Any polyhedron can be deformed (its angles changed) without affecting the number of edges, vertices or faces.

Rectangular prism Cube

A cube and a rectangular prism.

A cylinder and a cone - are two entirely different 3D shapes. A cylinder has three faces & two edges. A cone has two faces and one edge.

Three faces, two edges and 0 vertices.

Three faces, two edges and 0 vertices.

You cannot have such a shape because either the shapes must meet at an edge or the vertices must be joined by an edge.

There are two plane faces and a curved face, two edges and no vertices.

One edge, no vertices and two faces.

The numbers do not satisfy Euler's characteristic so there can be no such polyhedron.