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The Baseball will travel upwards until its velocity is zero and then fall back down again.

The acceleration of the baseball is the constant acceleration due to gravity acting in a downwards direction.

The time taken to fall back down will be the same as the time to climb, thus the total time is twice the climb time.

Use Netwon's equations of motion and ignore air resistance, the time to the top of the climb is:

v = u + at

→ t = v - u/a

v = final velocity = 0 m/s at the top of the climb

u = initial velocity = +100 m/s

a = acceleration = -g m/s²

t_top = 0 - (100 m/s) / (-g m/s²) = 100/g s

→ t_total = 2 × t_top = 2 × 100/g s = 200/g s ≈ 200/9.81 s ≈ 20.4 s

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βˆ™ 6y ago
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βˆ™ 6y ago

since gravity is accelerating down at 9.81 m/s/s, then at the top of its climb velocity is zero and it starts to fall back. velocity = acceleration x t ; 100 = 9.81 x time so time to climb is 10.2 seconds; another 10.2 seconds to fall is a total of 20.4 seconds to hit the ground. That's a long time and I don't think anyone can hit a baseball that hard!

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βˆ™ 6y ago

Approx 20.4 seconds.

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Anonymous

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βˆ™ 4y ago

10

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