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When You drop a rock from a cliff and 5.86 s later you see it hit the ground. How high is the cliff?
Wiki User
∙ 6y ago
You can use Newton's equations of motion:
s = ut + ½at²
Ignoring air resistance:
s = distance = height of cliff
u = initial velocity = 0 m/s
a = acceleration due to gravity ≈ 9.8 m/s²
t = time = 5.86 s
→ height of cliff ≈ ½ × 9.8 m/s² × (5.86 s)²
≈ 168 m
If you want it in feet:
0.3048 m = 1 ft (exactly)
→ 168 m = 168 m ÷ 0.3048 m/ft
≈ 551 ft
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoheight = 1/2 g t^2 where g = acceleration of gravity = 32 feet/sec/sec.height = 16 x 5.86 x 5.86 = 550 feet, or 167 meters
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