If you are still working with degrees, that is
360*k degrees to (1+2k)*180 degrees, for integer values of k.
NB: these are open intervals: that is, the end points are not included.
If you are still working with degrees, that is
360*k degrees to (1+2k)*180 degrees, for integer values of k.
NB: these are open intervals: that is, the end points are not included.
If you are still working with degrees, that is
360*k degrees to (1+2k)*180 degrees, for integer values of k.
NB: these are open intervals: that is, the end points are not included.
If you are still working with degrees, that is
360*k degrees to (1+2k)*180 degrees, for integer values of k.
NB: these are open intervals: that is, the end points are not included.
cosec(30) = 2 if the angle is measured in degrees.
2 + tansquareA + cossquareA
sec 45o = cosec 45o = √2 ≈ 1.414
cot(x) = sqrt[cosec^2(x) - 1]
tan cot sec cosec sin cos cot
d/dx cosec(x) = - cosec(x) * cot(x) so the second derivative or d(d/dx)/dx cosec(x) = [- cosec(x) * d/dx cot(x)] + [ - d/dx cosec(x) * cot(x)] = [- cosec(x) * -cosec^2(x)] + [ - (- cosec(x) * cot(x)) * cot(x)] = cosec(x) * cosec^2(x) + cosec(x)*cot^2(x) = cosec(x) * [cosec^2(x) + cot^2(x)].
Yes of course cosec x is the inverse of sin x by definition in trigonometry sin x=opp. side/hypotenuse cosec x= hypotenuse/opp.side thank u
cosec(x) <= -1 and cosec(x) >= 1Alternatively, it is all real numbers excluding the interval (-1, 1).
-cotan(x)
Sin cos sec cosec
You cannot since it is an irrational number.
cosec(30) = 2 if the angle is measured in degrees.
2 + tansquareA + cossquareA
codec, cosec, cusec, rebec, xebec, zebec
sec 45o = cosec 45o = √2 ≈ 1.414
cot(x) = sqrt[cosec^2(x) - 1]
sin(2x), cos(2x), cosec(2x), sec(2x), tan(x) and cot(x) are all possible functions.