There are 36 permutations of rolling two dice. Of these, 9 of them result in a sum of 9 or greater, specifically 6-3, 6-4, 6-5, 6-6, 5-4, 5-6, 4-5, 4-6, and 3-6.
The probability, then, of rolling a sum greater than 8 on a pair of fair dice is 9 in 36, or 1 in 4, or 0.25.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
If they are normal dice, the probability is 0.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
The probability is 1, if the dice are rolled often enough.
Probably.
The probability is 8/36 or 2/9
It is 1/6.
1/12 or .083