Sample space of the event = 6 x 6 = 36.
The possible order for the set of numbers whose sum would be 8 are (2,6),(3,5),(4,4),(5,3),(6,2). There are five such sets.
Therefore, Required probability = 5/36.
These are the probabilities you get when you roll two dice.To roll a...: your probability is ...
2: 1/36
3: 2/36
4: 3/36
5: 4/36
6: 5/36
7: 6/36
8: 5/36
9: 4/36
10: 3/36
11: 2/36
12: 1/36
The fractions above are NOT simplified - so that you can more clearly see the pattern. So for an "8", the probability is 5/36. This fraction can't be simplified.
1/9
Prob(Sum = 5) = 1/9
21/36 or 7/12 or 58.33...%
The probability is 1, if the dice are rolled often enough.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
It's1/12
1/9
Prob(Sum = 5) = 1/9
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
21/36 or 7/12 or 58.33...%
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
7
The probability is 1, if the dice are rolled often enough.
If the dice are fair then it is 5/36.
It is 1/9.
3
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.