The concept of a vertex, which is the intersecting point between two or more geometrical shapes, is meaningless in this case. A point can't have a vertex since it has no shape. A vertex, however can be a point. For example, if one 2-D line intersects another 2-D line, that point of intersection is the vertex.
16.7 is d ans
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
The next character in the series, "AB 3 D 56 G" is 8.
Draw a straight line ab putting the centre of compass at a take an arc which cuts ab at point c (let) from point c cut an arc with the same radius which u had taken while drawing the first this cuts the first arc at poiint d(let) join a-d and produce it in the direction of d angle bad is the required angle
this is a continuation of the question... AB=4, BC=6, AE=8, and BE intersects at D
96 TM!!!
CD
The concept of a vertex, which is the intersecting point between two or more geometrical shapes, is meaningless in this case. A point can't have a vertex since it has no shape. A vertex, however can be a point. For example, if one 2-D line intersects another 2-D line, that point of intersection is the vertex.
Gh. D. Pallade has written: 'Jurnal' -- subject(s): Diaries, Politicians, Politics and government, Sources
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If D > 0 then the graph intersects the x-axis 2 times.If D = 0 then the the x-axis is tangent to the graph.If D < 0 then the graph doe not intersects the x-axis.
16.7 is d ans
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
We're having a bit of trouble making out the line shown. "ab" and "ac" would not be the labels of a point ... they would be the labels of two line segments both emanating from the same point called "a". So your point has to be either 'b' or 'd' or both. We'll be able to put a finer point on it if you'll let us have a look at the picture of the line that goes along with the question.
D A Ab G F D, D A Ab G F, D A Ab G F, (Repeat this 2x) Bb F E D, B F E D, C E F G Bb A G A.
AB = 2 x 4 (8) C = 3 D = 5