Where would 2x plus 2y equals -6 be on a x- and y-intercept?

Answer 1

You really ought to be able to answer that question on your own.

The calculation is easier and quicker than typing it into a website.

2x + 2y = -6

At the x-intercept, y=0:

2x = -6

x = -3

At the y-intercept, x=0:

2y = -6

y = -3

In a slightly less condescending tone:

I interpret this as:

"Where are the x and y intercepts for the graph of 2x + 2y = -6?"

It might be helpful to first put this function in a more recognizable form as an explicit function of y:

2y = -6 - 2x

y = -x -3

The x-intercept(s) for this function will occur when the value of the variable y is zero, so simply substitute 0 in for y in the function:

0 = -x -3

-x = 3

x = -3

The x-intercept will occur at x = -3, which is the coordinate point (-3, 0).

The y-intercept for this function will occur when the value of the variable x is zero, so substitute 0 in for x to find it:

y = -0 - 3

y = -3

The y-intercept will occur at y = -3, which is the coordinate point (0, -3).

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The first contributor is flabbergasted:

Gee, that's so much more brief and clear!

Answer 2

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