100,000 cm = 1 km so 670 cm = 670/100,000 = 0.0067 km. Simple!
670 cm = 6.7 metres.
670 cm
No. The length of the longest stick must be less than the total length of the other two.
13 cm
6.7 meters = 670 cm (1 meter = 100 cm)
how is 670 cm in m
100,000 cm = 1 km so 670 cm = 670/100,000 = 0.0067 km. Simple!
670 cm = 6.7 metres.
Using Pythagoras' theorem the longest exterior diagonal is 19.209 cm to 3 dp
By unit of length and distance and conversion ,we can say that 1 cm =0.3930 in 67 cm=26.3 in
670 cm
No. The length of the longest stick must be less than the total length of the other two.
13 cm
The focal length of a lens can be calculated using the formula: ( \text{focal length (cm)} = \frac{1}{\text{power of lens (diopters)}} ). Substituting the given power of ( +1.5 \text{ D} ), we get ( \text{focal length (cm)} = \frac{1}{1.5} = 0.67 \text{ cm} ).
100 centimeters = 1 meter 670 centimeters = 670/100 = 6.7 meters
I am not sure what you mean by a "fundamental" number (I've never heard of that term being used with reference to the numbers themselves); I guess you mean an "integer". For a triangle to exist the shorter two sides must be longer than the longest side. Thus there is an upper limit to the length of the longest side of a triangle. For a given perimeter, the longest side must be less than half the perimeter. For a perimeter of 42cm this means that the longest side is less than 42 cm ÷ 2 = 21 cm. If we focus on the longest side of a triangle, as it becomes shorter, one or both of the other two sides must increase in length, they can equal but never be longer than this longest side. Thus there is also a lower limit below which the longest side cannot be; this is when all three sides are equal and the triangle is an equilateral triangle. For a perimeter of 42cm the longest side is greater than or equal to 42 cm ÷ 3 = 14 cm So with a perimeter of 42 cm we have: 14 cm ≤ longest side < 21 cm Which means for an integer length, the longest side can be 14 cm, 15 cm, 16 cm, 17 cm, 18 cm, 19 cm or 20 cm.