Circles have the biggest area for the same perimeter/circumference.
Perhaps you expected to get the same area with a longer rectangle. To see why this is not so - and help you visualize the problem - considere the following extreme case: a square of 1 x 1, and a "rectangle" of 2 x 0. (Or amost zero width - a very thin approximation will also do.) The perimeter is the same as for the square, but the area is zero (or near zero).
You can do this kind of maximization or minimization problem with calculus. You may learn about this later.
Circles have the biggest area for the same perimeter/circumference.
Perhaps you expected to get the same area with a longer rectangle. To see why this is not so - and help you visualize the problem - considere the following extreme case: a square of 1 x 1, and a "rectangle" of 2 x 0. (Or amost zero width - a very thin approximation will also do.) The perimeter is the same as for the square, but the area is zero (or near zero).
You can do this kind of maximization or minimization problem with calculus. You may learn about this later.
Circles have the biggest area for the same perimeter/circumference.
Perhaps you expected to get the same area with a longer rectangle. To see why this is not so - and help you visualize the problem - considere the following extreme case: a square of 1 x 1, and a "rectangle" of 2 x 0. (Or amost zero width - a very thin approximation will also do.) The perimeter is the same as for the square, but the area is zero (or near zero).
You can do this kind of maximization or minimization problem with calculus. You may learn about this later.
Circles have the biggest area for the same perimeter/circumference.
Perhaps you expected to get the same area with a longer rectangle. To see why this is not so - and help you visualize the problem - considere the following extreme case: a square of 1 x 1, and a "rectangle" of 2 x 0. (Or amost zero width - a very thin approximation will also do.) The perimeter is the same as for the square, but the area is zero (or near zero).
You can do this kind of maximization or minimization problem with calculus. You may learn about this later.
Circles have the biggest area for the same perimeter/circumference.
Perhaps you expected to get the same area with a longer rectangle. To see why this is not so - and help you visualize the problem - considere the following extreme case: a square of 1 x 1, and a "rectangle" of 2 x 0. (Or amost zero width - a very thin approximation will also do.) The perimeter is the same as for the square, but the area is zero (or near zero).
You can do this kind of maximization or minimization problem with calculus. You may learn about this later.
Then they both will have the same perimeter
32
40cm
20 cm
20 cm
The perimeter is four.
The perimeter is 24 feet.
Then they both will have the same perimeter
A square with a perimeter of 32 inches has an area of 64 square inches.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
32
40cm
40 cm
20 cm
32 cm
yes
20 cm