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# Why does 15 not belong in the number series of 15 2 8 13 16?

Updated: 10/18/2022

Wiki User

11y ago

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Wiki User

11y ago

Wiki User

11y ago

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.