Of course it does.
Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.
In this case, try
Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.
So, the question is misguided.
Of course it does.
Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.
In this case, try
Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.
So, the question is misguided.
Of course it does.
Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.
In this case, try
Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.
So, the question is misguided.
Of course it does.
Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.
In this case, try
Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.
So, the question is misguided.
Of course it does.
Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.
In this case, try
Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.
So, the question is misguided.
17
11
17 :)
No, 13 is a prime number and 15 is a composite number. A composite number is a positive integer that has more than two positive divisors.
13 is prime.
17
The series 1 6 10 13 15 (1+5=6; 6+4=10, 10+3=13; 13+2=15) is completed by 15+1=16. The answer is 16.
The answer is 12 every other numbers are odd numbers, but 12 is an even number
What would be the next number in this series 15 12 13 10 11 8?
11
you are adding 2, so its 17
11
13, it's the only prime. All the other ones can be divided by something other than 1.
17 :)
Each one of them. 15: the only semi-prime in the list 2: the only even prime in the list 8: the only perfect cube in the list 13: the only odd prime in the list 16: the only perfect square in the list. Take your pick!
Take your pick: 15 because it is a product of two prime numbers 2 because it is the only even prime number 8 because it is the smallest cube that is not the same as its root (03 = 0 and 13 = 1) 13 because it is an odd prime 16 because it is a square as well as a fourth power.
The answer depends on which one you would like it to be:2, it is the only even prime;8, it is the only perfect cube in the list;13, because it is the only odd prime number in the list;15, because it is the only number in the list with different prime factors; and16, it is the only number with an odd number of divisors.Take your pick!