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Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

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11y ago
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Wiki User

11y ago

Of course it does.

Given any set of n numbers, it is ALWAYS possible to find a polynomial of degree (n-1) such that the polynomial generates those numbers.

In this case, try

Un = (19n4 - 270n3 + 1373n2 - 2826n + 2064)/24 for n = 1, 2, 3, 4 etc.

So, the question is misguided.

This answer is:
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Q: Why does 15 not belong in the number series of 15 2 8 13 16?
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The next number in this series 7 9 11 13 15 is?

17


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What would be the next number in this series 15 12 13 10 11 8?


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Which one of the number does not belong in the following series 15 - 2 - 8 - 13 - 16?

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Which number does not belong 2 8 13 15 16?

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