It ends with a 5 and so is evenly divisible by 5.
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Yes. 55 is a composite number and it is divisible by 1, 5, 11, 55
21, 55, 77, and 93 are composite numbers. 23 is a prime.
The composite factors of 1485 are 9, 15, 27, 33, 45, 55, 99, 135, 165, 297, 495, 1485
composite because it has more than two factors
Prime numbers are numbers that can only be multiplied itself and one.For ex.87 is a prime number. You can't multiply a number to get 87. Composite is a number that can be multiplied by other numbers than itself. For ex.55 is a commposite number. 11 and 5 can get you 55. Hope u understand! Good luck!