I assume x2 + 5x - 36 is the polynomial in the question. First, look for two factors of 36 that have a difference of 5, which would be 9 and 4. It would factor into (x + 9)(x - 4). To double check, multiplying them together results in x2 - 4x + 9x - 36 = x2 + 5x - 36. If the polynomial is 5x2 +7x +2
n^2(n + 6)(n^2 - 6n + 36)
36/60 = 3/5 (removing the common factor 12).
36 is the highest factor of 36.
2(x + 6)(x - 6) 2x^2 - 72 = 0 2x^2 = 72 x^2 = 36 x = 6, -6
I assume x2 + 5x - 36 is the polynomial in the question. First, look for two factors of 36 that have a difference of 5, which would be 9 and 4. It would factor into (x + 9)(x - 4). To double check, multiplying them together results in x2 - 4x + 9x - 36 = x2 + 5x - 36. If the polynomial is 5x2 +7x +2
36
6.(x2 + 12x + 36) = 6.(x + 6)(x + 6)
n^2(n + 6)(n^2 - 6n + 36)
The factor pairs of 36 are (36,1)(18,2)(12,3)(9,4)(6,6) Since 36 is a perfect square, the factor 6 is repeated. 6 x 6 = 36
It ia: 6*6 = 36
TrUE
False. It has to be either "- 24x" or "+ 36". These would factor as (3x - 4)2 and (3x - 6)2 respectively.
2 x 2 x 3 x 3 = 36
x2 + 15x +36
36
38