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In this case, it helps to use the quadratic formula on the numerator of the fraction.
(x2-25)=(x+5)(x-5)
Now, substituting this back into the fraction, we are able to cancel out he (x+5) term from both the numerator and denominator. Thus, the answer is (x2-25)/(x+5)=(x-5).
(3y - 5)(y + 5)
x = 25 / 3squared + 5
The centre is (-5, 3)
25 squared plus 49 squared is equal to 3,026.
zero