5000 students participated in a certain test yielding a result that follows the normal distribution with means of 65 points and standard deviation of 10 points.
(1) Find the probability of a certain student marking more than 75 points and less than 85 points inclusive.
(2) A student needs more than what point to be positioned within top 5% of the participants in this test?
(3) A student with more than what point can be positioned within top 100 students?
i dont understand the question.. could you help me??pls....
It would be approximately normal with a mean of 2.02 dollars and a standard error of 3.00 dollars.
about 25
68 % is about one standard deviation - so there score would be between 64 and 80 (72 +/- 8)
It is the sample mean age of 21.7.
The null hypothesis could be that the 40 students are a sample from the same (or similar) population.
Not possible to tell you without knowing how many students' there are, and what distribution you wish to use (i.e normal distribution, t-distribution etc...)
Standard deviation is 0.
(x-400)/100=1.882 x=588.2
To see how wide spread the results are. If the average (mean) grade for a certain test is 60 percent and the standard deviation is 30, then about half of the students are not studying. But if the mean is 60 and the standard deviation is 5 then the teacher is doing something wrong.
It would be approximately normal with a mean of 2.02 dollars and a standard error of 3.00 dollars.
IQ scores for adult students age 25-45 have a bell-shaped distribution with a mean of 100 and a standard deviation of 15.sing the Empirical Rule, what percentage of adult students age 25-45 have IQ scores between 70 and 130?
about 25
68 % is about one standard deviation - so there score would be between 64 and 80 (72 +/- 8)
It is the sample mean age of 21.7.
The null hypothesis could be that the 40 students are a sample from the same (or similar) population.
There are approximately 16.4% of students who score below 66 on the exam.
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