8.
the probability of getting one head and one tail on three flips of a coin is 1/9
In three tosses there can be four possible outcomes: three heads, three tails, two heads and one tail, and one head and two tails. ^^^That is wrongA coin is tossed N times. There are 2 possibilities when you toss a coin: heads and tails.So the formula is 2^N (thats to the N power)A coin tossed 3 times has 2^3=8 possible outcomes:head head headhead head tailhead tail headtail head headtail tail headhead tail tailtail head tailtail tail tailThere they are!
Coin tosses are independent events. The probability of a head remains 1/2
0.5, 1/2, 50% The probability for heads versus tails does not change based on the amount of times the coin is tossed. It will always be a 50% chance.
1 in 12 chance
the probablity of getting a head is 1/2 and 7 heads consecutively is (1/2)^7
2
285 out of 500
8.
obviously it is a 50-50 chance
Assuming that it is a fair coin, the probability is 0.9990
The probability is 50-50.
It means that if the coin were tossed an infinite number of times, half of the tosses would come up heads and half would be tails.
The probability is 1/4
Mean = 2. Variance = 1.
To calculate the probability of getting only one head and an even number on the tetrahedral die, we need to consider the total number of possible outcomes. There are 2 outcomes for the coin toss (HH, HT), and 2 outcomes for the tetrahedral die (2, 4). Therefore, there are a total of 2 x 2 = 4 possible outcomes. The favorable outcome for getting only one head and an even number is (HT, 2) or (HT, 4), which is 2 out of the 4 possible outcomes. Thus, the probability is 2/4 = 0.5 or 50%.