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It is possible to choose 4 radios out of 23 in (23 choose 4)=8855 ways. The number of those combinations where there are exactly 2 indefective and 2 defective is: (18 (the number of those indefective) choose 2)*(5 (the number of defective radios) choose 2)=1530 divided by 8855=1530/8855=306/1771 which is 17.2784%.

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Q: A department store receives a shipment of 23 new portable radios There are 5 defective radios in the shipment If 4 radios are selected for display What is the probability that 2 of them are defective?
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