A fair coin is tossed four times. What is the probability of getting some combination of three heads and one tail regardless of the order?

Answer 1

The probability of getting a combination of three heads and one tail regardless of the

order when you toss a coin four times is:

P(THHH or HTHH or HHTH or HHHT) = P(THHH) + P(HTHH) + P(HHTH) + P(HHHT) =

1/2(1/2)(1/2)(1/2) + 1/2(1/2)(1/2)(1/2) +1/2(1/2)(1/2)(1/2) + 1/2(1/2)(1/2)(1/2) = 4/16 = 1/4