5 out of 12
Probably.
The two dice sum of 4: 1,3 2,2 3,1 = 3 in 36 = 1 in 12
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
You must notice that it is easier to find the probability that none of the dice are six. This is the complement of the answer. Pc= (55)/(65) = .4019 *the first die has 5 ways to not equal six, and so on for the remaining dice. [55] outcomes have no six. *the total number of outcomes gives each die 6 ways to fall. [65] outcomes overall. *Probability is the favorable outcome divided by the total number of outcomes. *Probability of an event is 1 minus the complement of the event. P = 1 - .4019 P = .5981 <<<<<<FINAL ANSWER
Assuming these are regular dice, the probability is 1.
5 out of 12
The probability is 35/36.
The probability is 8/36 or 2/9
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
Probably.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
The two dice sum of 4: 1,3 2,2 3,1 = 3 in 36 = 1 in 12
There is an approximately 8% chance of that, or 1 out of 12.
It is 15/36 = 5/12
1/3 or 4/12
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.