The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.
The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.
The probability of rolling a 1 on the second roll is 1/6.
If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.
The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.
Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:
3/6 + 1/6 - 3/36
= 18/36 + 6/36 - 3/36
= 21/36
= 7/12
2/6 or 1/3 or 0.3333.
There could be many questions: What is the probability of rolling an even number. What is the probability of rolling an odd number. What is the probability of rolling a number less than 4. What is the probability of rolling a number more than 3. What is the probability of rolling 1,4, or 6. Basically it could be any question about the probability of rolling half of the faces.
The factors of 10 are the numbers that divide 10 evenly: 1, 2, 5 and 10. To answer your question, you have to figure out what the probability of rolling one of these numbers is on a number cube.
The probability is 11/36.
The probability of rolling a number greater than 6 on a die is 0.
2/6 or 1/3 or 0.3333.
There could be many questions: What is the probability of rolling an even number. What is the probability of rolling an odd number. What is the probability of rolling a number less than 4. What is the probability of rolling a number more than 3. What is the probability of rolling 1,4, or 6. Basically it could be any question about the probability of rolling half of the faces.
The factors of 10 are the numbers that divide 10 evenly: 1, 2, 5 and 10. To answer your question, you have to figure out what the probability of rolling one of these numbers is on a number cube.
The probability of rolling a three or a four (meaning one roll, and either number would be counted a "success") is 1/3. This is because the probability of rolling a three is 1/6, the probability of rolling a four is 1/6, and if you are good with either possibility, then the combined probability is 1/6+1/6 = 1/3.
The probability is 11/36.
when rolling a number cube when rolling a number cube what is the probability of rolling an even number or a divisor of 10? rolling an even number or a divisor of 10?
The probability of flipping tails on a perfect coin in a perfect toss is 0.5. The probability of rolling 1 on a die is 1 in 6. Likewise, the probability of rolling 6 on a die is 1 in 6. So the probability of rolling either 1 or 6 is 2 in 6 (which is 1 in 3).
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
The probability of rolling a number greater than 6 on a die is 0.
The probability would be 5/6 for rolling a number other than a 3.
A standard six-sided die has 3 even numbers and 3 odd ones, so the probability of rolling either an odd or even number would be 50-50.
The probability of rolling an odd number on a standard die is 3 in 6, or 1 in 2, or 0.5.