all that matters in this problem, is that 2 of the 13 spaces are orange.
On the first spin, the odds are 11:2 against Jake getting the orange space.
On the second spin, the result of the first spin has no relevance or influence at all, so the odds are still 11:2 against.
Why is this question flagging up in "breakups"?
Assuming you want the probability FOR A SINGLE TRY, and you want the numbers in that exact order, the probability for each part (for instance, first = red; or second = green) is 1/4; therefore, the probability for the combination is (1/4) to the power 4.
3/5=g/30
What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)
To determine the probability that a randomly thrown dart hits a blue or yellow region on a square board, you need to know the areas of the blue and yellow regions in relation to the total area of the square board. The probability can be calculated by dividing the combined area of the blue and yellow regions by the total area of the board. If the areas are not specified, you cannot provide a numerical probability. Therefore, the probability is given by the formula: P(blue or yellow) = (Area of blue + Area of yellow) / (Area of the square board).
3/4
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
the same as it is the first time 1/5
you will only get 3 orange and 2 yellow
An orange is not yellow simply because it was orange and that is the way it was intended to be not yellow. Also, if the Orange was yellow, then it would be called a yellow. Not an Orange.
There are 6 possible outcomes.There are 6 possible outcomes.There are 6 possible outcomes.There are 6 possible outcomes.
Assuming you want the probability FOR A SINGLE TRY, and you want the numbers in that exact order, the probability for each part (for instance, first = red; or second = green) is 1/4; therefore, the probability for the combination is (1/4) to the power 4.
Orange-yellow (if there's more yellow), also known as golden yellow, or yellow-orange (if there's more orange).
Orange-yellow (if there's more yellow), also known as golden yellow, or yellow-orange (if there's more orange).
Orange-yellow (if there's more yellow), also known as golden yellow, or yellow-orange (if there's more orange).
4 colours = 1 divided by 4 = 1 quarter per colourred + blue = 1/4 +1/4 = 1/2
Simply a lighter orange and and a more orange yellow.
yellow yellow green aqua aqua green yellow orange red red orange yellow yellow orange orange