Yes, 1, 2, 3, and 6 will Can_you_write_12_using_the_same_digits_none_of_them_being_4. Examples: 1+1+1+1+1+1+1+1+1+1+1+1=12 and 2+2+2+2+2+2=12 and 3+3+3+3=12 and 6+6=12.
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None.
There are 5 choices for the first digit, as any of the 5 given digits can be used. After selecting the first digit, there are 4 remaining choices for the second digit, and 3 choices for the third digit. Therefore, the total number of ways to write a 3-digit positive integer using the given digits without repetition is 5 x 4 x 3 = 60 ways.
None. The only way for it to be possible would be 3 zeros which is not considered a 3 digit numbers.
Typically, no. While a researcher might anticipate a particular result, the hypothesis is only that - what the expected result might be (and often, there may be several possible expected results or even none.)
None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits.
There are none.
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
There are no didgits. None! They do not exist! There are ten digits 0, 1, ... 9 which represent the first ten numbers. Beyond that, numbers are represented using the same ten digits but this is done using the idea of place values.
One - the four. None of the trailing 0s are significant digits.
There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.
None.
none
The ones column are in single digits and if there are none then the 0 digit is used.
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None. icici is not a number.
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74