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You find the sample space by enumerating all of the possible outcomes. The sample space for three coins is [TTT, TTH, THT, THH, HTT, HTH, HHT, HHH].

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Q: How do you find the sample space of tossing 3 coins?
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writer sample space associated with the experiment of tossing 3 coins at the time and the event of getting heads from the first 2 coins.aslo find the correspondind probability?

[object Object]


Find the sample space for tossing a coin and spinning the spinner at the right. (The spinner has 5 equal sections)?

The sample space is H1, H2, H3, H4, H5, T1, T2, T3, T4, T5.


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It is 15/16.


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Sample space: {hhh,hht,hth,htt,ttt,tth,tht,thh} 8 possible outcomes


When tossing 3 coins simultaneously find the probability that at least 1 head is showing?

No matter how many coins are thrown, the possibility of having AT LEAST ONE 'head' is 50%. This changes if you specify the number of 'heads' that must be shown.


What is a pascal's triangle used for?

It is used for lots of things such as finding out the total possible outcomes of tossing coins. You find the line that corresponds with how many coins you toss and add all the numbers in that line to get the number of possible outcomes also you can use it to find combinations and permutations and triangular numbers


Find the sample space for three question multiple-choice test with five choices?

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What does find the size of the sample space mean?

A concept in probability theory which considers all possible outcomes of an experiment, game, and so on, as points in a space.


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The sample space for choosing a letter from the word SPACE is {S, P, A, C, E}. The sample space for choosing a consonant from the word MATH is {M, T, H}. Consonants are letters that are not vowels (A, E, I, O, U), so in the word MATH, the consonants are M, T, and H.


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Why do you find the sample space for an experiment to find the probability of an even?

You do not need to but it can help to identify all the possible outcomes so that you don't miss any out (by mistake).


When tossing 5 coins simultaneously can you find the probability that at least 1 head is showing?

Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32