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You think of each toss as having heads or tails, so there are two choices. If you toss the coin twice you have 4 choices HH, TT, HT and TH. The number of different coin tosses is 2n ordered tosses and n+1 unordered. For example in two tosses, 22=4 ordered tosses if HT is different than TH and if HT is the same as TH then we have 2+1=3 different possible tosses. So using this if we toss a coin 5 times and order does not matter, there are 6 different possibilities. These are HHHHH, TTTTT, HTTTT, HHTTT, HHHTT, HHHHT,HHHHH.

If order matters, there are 25=32 different possible ways to toss a coin 5 times. For example, HHHHT is different than THHHH. I will not write them all out, but you can do it easily by starting with HHHHH and changing each H to a T then two H to T and then 3, etc.

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Q: How do you find the sample space of tossing a coin 5 times?
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