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The first letter can be any one of 22. For each of these ...
The second letter can be any one of the remaining 21. For each of these ...
The third letter can be any one of the remaining 20.
So the number of different 3-letter line-ups is (22 x 21 x 20) = 9,240.
That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.
If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are all
the same to you, then there are six ways to arrange each group of 3 different letters.
Then the total number of different picks is (9,240/6) = 1,540.
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How many different five-letter initials with none of the letters repeated can people have?
There are 26*25*24*23*22 = 7,893,600 sets of initials.
How many combinations can you make with 5 letters?
We first make an assumption that you are picking 5 letters from 26. If this is not the case, the problem is different. This is covered at the end of the answer. With repetition allowed (letters can be re-used), and order is not important since it is a combination (not a permutation), it is (26+5-1)!/(5!)(26-1)! This is a really big number! If it were a permutation with repetition, this is the same as the number of ways to pick 5 things from 26 with replacement. There are 26 choices for each letter, so you have 26x26x26x26x26 permutations. No repetition, order is important, it is 26! / (26-5)! = 26 x 25 x 24 x 23 x 22 = 7,893,600 No repetition, order doesn't matter (ABCDE is the same as EDCBA is the same as CEDAB, etc), it is 26! / (5!(26-5)!) = (26 x 25 x 24 x 23 x 22)/(5 x 4 x 3 x 2 x 1) = 65,780 What if you just have 5 letter already picked. Meaning you are not worried about picking the 5 from the alphabet, you already have 5 fixed letter. Some may be the same letter or not. If you allow for repetition of the letters, you have 5x5x5x5x5 permutations. For combinations, it would be 11!/5!4!=7983360 MOST LIKELY, you just have 5 distinct letters and you want to arrange them where order does matter and you cannnot repeat. In this case you have 5 choices for the first letter, 4 for the second, 3 for the third etc. So you have 5! or 120 choices. Of course if you have 5 things and the order does not matter, there is only 1 way to arrange them. For example. ABCDE is the same as ABEDC. So in dealing with combinations and permuations, the language must be quite exact. A small difference changes the entire problem. See related MathsIsFun link for more information.
How many cotton bolls in t-shirt?
22
You need to have a password with five letters followed by 2 odd digits between 0-9 inclusively If the characters and digits cannot be used more than once how many choices do you have?
(26 x 25 x 24 x 23 x 22) x (5 x 4) = 157,872,000
What is a estimate of 15 percent of 22?
15% of 22 = 15% * 22 = 0.15 * 22 = 3.3
How many eight letter combinations can you make using the twenty six letters of the alphabet wihtout using the same letters over?
26*25*24*23*22*21*20*19 = 62,990,928,000
How many 2 combinations are there in 22?
11
How many Hebrew 3 letter monograms are there?
There are 22 letters in the Hebrew alphabet. If you assume that any 3 letters could be a monogram, the answer is 10,648.
How many combination of 24 letters?
The answer can be written as "24!" or 24 factorial, which means 24 X 23 X 22 .... X 3 X 2 X1. The answer is 620,448,401,733,239,439,360,000 different combinations. --------------------------------------------------------------------------------------------- The question should say "permutations of 24 different letters" I believe, for which the above answer is. Number of 24 different letter permutations.
How many letter passwords can be formed from ABCs with no repeat?
That depends - on how many letters are in the password - AND - if any letter can be repeated. For example... an eight-digit password has 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 = 208,827,064,576 possible combinations IF every letter can b repeated. If each letter can only be used once, then the formula is 26 x 25 x 24 x 23 x 22 x 21 x 20 x19 = 62,990,928,000 possible combinations.
How many combinations of coins can make 85 cents?
22
How many combinations of coins can be made into 36 cents?
22
How many letters are there in the Phoenician alphabet?
22 letters
How many letters are the in Phoenicians?
It had 22.
How many letters are in the phonecian alphabet?
There were 22 letters in the Phoenician alphabet.
What is the 36th letter of the Hebrew alphabet?
The Hebrew alphabet only has 22 letters. (the 5 Final forms do not count as separate letters, and are not listed in the alphabet).The letters in alphabetical order are:אבגדהוזחטיכלמנסעפצקרשת
How many letters were in the Phoenician alphapet?
22.
