The number of combinations is 39*38*37*36*35 / (5*4*3*2*1)
= 575757
36 P 5. n P r This is a permutation so it's 35+35+34+33+32
1470 * * * * * That is sheer nonsense! The correct answer is 49C6 = 49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816
Three: they are 3, 5 and 6.
The number of outcomes you would have is number of outcomes x number of times done. Or in this case, number (of outcomes on the dice) x 5 x 5 x 5 x 5 x 5 because you rolled the dice 5 times
If 5 is a factor of a number, it means the number is divisible by 5. For the ones digit of the number to be 5, the number must end in 5. Since there are 10 possible digits (0-9), and only one of those digits is 5, the probability of the ones digit being 5 is 1 out of 10, or 1/10.
5.695 as a mixed number = 5 139/200
As a product of its prime factors: 2*3*3*5*139 = 12510 or as 2*32*5*139 = 12510
89 + (5 x 10) = 139
139
458,377,920 for 5 and 21,085,384,320 with the 6th number you need
27.8
139 + 5
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
27 R 4
1, 5, 139, 695 5 and 139 are prime.
5 days 19 hours
Chiquititas - 1995 5-139 is rated/received certificates of: Argentina:Atp