The number of combinations is 39*38*37*36*35 / (5*4*3*2*1)
= 575757
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36 P 5. n P r This is a permutation so it's 35+35+34+33+32
1470 * * * * * That is sheer nonsense! The correct answer is 49C6 = 49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816
Three: they are 3, 5 and 6.
The number of outcomes you would have is number of outcomes x number of times done. Or in this case, number (of outcomes on the dice) x 5 x 5 x 5 x 5 x 5 because you rolled the dice 5 times
If 5 is a factor of a number, it means the number is divisible by 5. For the ones digit of the number to be 5, the number must end in 5. Since there are 10 possible digits (0-9), and only one of those digits is 5, the probability of the ones digit being 5 is 1 out of 10, or 1/10.