The number of combinations is 39*38*37*36*35 / (5*4*3*2*1)
= 575757
36 P 5. n P r This is a permutation so it's 35+35+34+33+32
1470 * * * * * That is sheer nonsense! The correct answer is 49C6 = 49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816
Three: they are 3, 5 and 6.
The number of outcomes you would have is number of outcomes x number of times done. Or in this case, number (of outcomes on the dice) x 5 x 5 x 5 x 5 x 5 because you rolled the dice 5 times
If 5 is a factor of a number, it means the number is divisible by 5. For the ones digit of the number to be 5, the number must end in 5. Since there are 10 possible digits (0-9), and only one of those digits is 5, the probability of the ones digit being 5 is 1 out of 10, or 1/10.
5.695 as a mixed number = 5 139/200
As a product of its prime factors: 2*3*3*5*139 = 12510 or as 2*32*5*139 = 12510
89 + (5 x 10) = 139
139
458,377,920 for 5 and 21,085,384,320 with the 6th number you need
27.8
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
139 + 5
27 R 4
1, 5, 139, 695 5 and 139 are prime.
5 days 19 hours
Chiquititas - 1995 5-139 is rated/received certificates of: Argentina:Atp