First digit can be any of 3, second can be any of 3, as can third and fourth so your answer is 3 to the fourth ie 81
2222
If you want 4-digit numbers, there are 24 of them.
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
Most people prefer to write numbers using digits since this is far shorter than writing out the relevant words.
Assuming each of the given digits can be used only once, the answer is 24. If not, the answer is infinity.
89,999 different numbers i guess
If the digits are all different then 18. Otherwise, 192.
2222
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
99999
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
It is possible to create infinitely many numbers, of infinitely many different lengths, using the digits of the given number. Using each of the digits, and only once, there are 5! = 120 different permutations.
Base two is also referred to as the binary number system.In the decimal system we use 10 different digits (0 to 9) to represent numbers. However, all numbers in binary consist of a combination of only 2 different digits; a "0" and/or a "1".All numbers can be represented using only these 2 digits.
60
10+23 = 33
With base one million, you can create one nonillion different numbers; using the traditional decimal (base ten) system, you can form 100 thousand different numbers.
If they can be repeated, 343 different numbers. If they can be used once each, there are only 210.